Example 7: nominal moment for reinforced concrete T beam (Si units)
Determine nominal moment Mn for beam in figure 1.
Assuming a<80mm
a=(As*fy)/(0.85*fc'*b)
a=(6*1006*300)/(0.85*28*800)
a=95.1mm
the assumption is wrong, therefore a>80mm
0.85*fc'*a1*b1+0.85*fc'*a2*b2=As.fy
0.85*28*80*800+0.85*28*a2*350=6,036*300
a2=34.52
F1=0.85*fc'*a1*b1
F1=0.85*28*80*800
F1=1,523,200N=1,523.20Kn
F2=0.85*fc'*a2*b2
F2=0.85*28*34.52*350
F2=287,551.6N=287.55Kn
Center of compressive force, extreme compression fiber(top of the beam) is the reference axis
X=(F1*40+F2*97.26)/(F1+F2)
X=(1523.2*40+287.55*97.26)/(1523.2+287.55)
X=49mm
a moment can be calculated by multiplying a couple of force with equal magnitude and opposite direction by the vertical distance between them
Mn=As*fy*(381)
Mn=689,914,800 N.mm=689.9Kn.m
Figure 1
a=(As*fy)/(0.85*fc'*b)
a=(6*1006*300)/(0.85*28*800)
a=95.1mm
the assumption is wrong, therefore a>80mm
0.85*fc'*a1*b1+0.85*fc'*a2*b2=As.fy
0.85*28*80*800+0.85*28*a2*350=6,036*300
a2=34.52
F1=0.85*fc'*a1*b1
F1=0.85*28*80*800
F1=1,523,200N=1,523.20Kn
F2=0.85*fc'*a2*b2
F2=0.85*28*34.52*350
F2=287,551.6N=287.55Kn
Center of compressive force, extreme compression fiber(top of the beam) is the reference axis
X=(F1*40+F2*97.26)/(F1+F2)
X=(1523.2*40+287.55*97.26)/(1523.2+287.55)
X=49mm
a moment can be calculated by multiplying a couple of force with equal magnitude and opposite direction by the vertical distance between them
Mn=As*fy*(381)
Mn=689,914,800 N.mm=689.9Kn.m


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